Given that -6.6 is some number of times as large as 5.
Let x be the required number.
Given can be written as follows.
[tex]-6.6=5\times x[/tex][tex]\text{Use 6.6=}\frac{66}{10}\text{.}[/tex][tex]-\frac{66}{10}=5x[/tex]Dividing by 5 into both sides, we get
[tex]-\frac{66}{10\times5}=\frac{5x}{5}[/tex][tex]-\frac{66}{50}=x[/tex]Dividing 66 by 50, we get 1.32.
[tex]x=-1.32[/tex]Hence the required number is -1.32.
