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A certain rare form of cancer occurs in 37 children in a million, so its probability is 0.000037. In the city of Normalville there are 74,090,000 children. A Poisson distribution will be used to approximate the probability that the number of cases of the disease in Normalville children is more than 2. Find the mean of the appropriate Poisson distribution (the mean number of cases in groups of 74,090,000 children).

Respuesta :

SOLUTION:

Using Poisson distribution

[tex],u=np[/tex]

n = 74,090,000

p = 0.000037

Therefore, the mean of the appropriate Poisson distribution

[tex]\begin{gathered} =74,090,000\times0.000037 \\ =2741.33 \end{gathered}[/tex]

Final answer: Nearest whole number

2470

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