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determine what element undergoes oxidation and what element undergoes reduction in 3H2SO4 + 2KMnO4 + 5H2O2 --> 5O2 + 2MnSO4 + 8H2O + K2SO4Write NA if not applicable

Respuesta :

Answer

H₂O₂ undergoes oxidation

KMnO₄ undergoes reduction

Explanation

Given equation:

3H2SO4 + 2KMnO4 + 5H2O2 --> 5O2 + 2MnSO4 + 8H2O + K2SO4

The oxidation number of O in H₂O₂ is -1 and this changes to o in O₂ on the product side. Hence, H₂O₂ undergoes oxidation.

The oxidation number of Mn in KMnO₄ is +7 and changes to +2 in MnSO₄ on the product side. Therefore, KMnO₄ undergoes reduction.

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