a Bismuth-210 has a half-life of about 5 days. After 17 days, how many milligrams of a 1,728 mg sample will remain? Round answer to the nearest tenth place. If answer does not have tenths place use a zero so that it does.

Respuesta :

Step-by-step explanation:

We have been given that Bismuth-210 has a half-life of about 5 days.

To solve our given problem we will use half-life formula.

[tex]y=a\times(\frac{1}{2})^{\frac{t}{b}}[/tex]

Where,

a = Initial value,

t = Time,

b = half-life.

Given:

[tex]\begin{gathered} a=1728mg \\ t=17 \\ b=5 \end{gathered}[/tex]

Therefore,

[tex]y=1728(\frac{1}{2})^{\frac{17}{5}}[/tex]

Simplify

[tex]y=163.69738\approx163.7mg[/tex]

Hence, the answer is

[tex]163.7mg[/tex]