Hello there. To solve this question, we'll have to remember some properties about finding the area of polygons.
First, notice the area of this window is a merge of the areas of a rectangle, with length 5 dm and width 12 dm, and a semicircle with diameter 5 dm (since its bottom is parallel to the rectangle).
In this case, remember the formulas for:
Area of a rectangle
Area of a semicircle (diameter)
Therefore the area of the window will be given by:
Using 3.14 as an approximation for pi, we have:
[tex]A\approx69.8dm^2[/tex]
This is the area of the window we've been looking for.
