Given data
*The given time interval is t = 2.62 s
*The given angular velocity is
[tex]\omega=29\text{ rad/s}[/tex]*The given number of revolutions is 9 revolutions.
The formula for the constant angular acceleration is calculated by the rotational equation of motion as
[tex]\theta=\omega t-\frac{1}{2}\alpha t^2^{}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} 9\times2\pi=29\times2.62-\frac{1}{2}(\alpha)(2.62)^2 \\ \alpha=5.66rad/s^2 \end{gathered}[/tex]Hence, the constant angular acceleration is 5.66 rad/s^2
