For each case, we will use the next formula
[tex]\lambda=\frac{v}{f}[/tex]where λ is the wavelength, v is the wave speed and f is the frequency
in this case
f=1000s^-1
A.
Lead
v=1230 m/s
we susbtitute
[tex]\lambda=\frac{1230}{1000}=1.23m[/tex]B. Hydrogen
v=1267 m/s
[tex]\lambda=\frac{1267}{1000}=1.267m[/tex]C. Water
v=5250 km/h
In this case we need to change the km/hr to m/s
that can be done by dividing km/hr between 3.6
v=1458.33 m/s
Then we substitute
[tex]\lambda=\frac{1458.33}{1000}=1.458m[/tex]D. Air
v=1234 km/h
we need to convert km/h
v=342.8m/s
[tex]\lambda=\frac{342.8}{1000}=0.3428m[/tex]ANSWER
A.1.23 m
B.1.267 m
C.1.458 m
D.0.3428 m
