Respuesta :
Explanation
From the statement, we know that a rectangle has:
• a perimeter P = 108.13 in,
,• height l = 5.46 in + w, being w the width.
We want to find the dimensions of the rectangle.
(a) Width
The perimeter of the rectangle is given by:
[tex]P=2l+2w.[/tex]Where l is the length and w is the width.
Replacing the data from above, we have:
[tex]\begin{gathered} 108.13in=2\cdot(5.46in+w)+2w, \\ 108.13in=10.92in+4w. \end{gathered}[/tex]Solving for w, we get:
[tex]\begin{gathered} 4w=108.13in-10.92in, \\ 4w=97.21in, \\ w=\frac{97.21in}{4}=24.3025in, \\ w\cong24.30in. \end{gathered}[/tex](b) Length
Using the result for the width, we compute the length:
[tex]l\cong5.46in+24.30in=29.76in.[/tex]Answer• The width is ,24.30 in
,• The length is ,29.76 in
