Given the equation:
[tex]y=x^2+12x+27[/tex]
We will find the x-intercepts of the function y
The x-intercept is the value of (x) when y = 0
So, we will substitute with y = 0 then solve the equation to find x
[tex]\begin{gathered} x^2+12x+27=0 \\ \end{gathered}[/tex]
Factor the equation to find the roots:
[tex]\begin{gathered} (x+9)(x+3)=0 \\ x+9=0\rightarrow x=-9 \\ x+3=0\rightarrow x=-3 \end{gathered}[/tex]
So, the answer will be:
The x-intercepts are the points (-9, 0) and (-3, 0)
