we have:
arc NPL = 2 arcNL
[tex]\begin{gathered} arcNPL+arcNL=360 \\ 2\text{arcNL}+\text{arcNL}=360 \\ 3\text{arcNL}=360 \\ \frac{3}{3}\text{arcNL}=\frac{360}{3} \\ \text{arcNL}=120 \\ \end{gathered}[/tex]then
[tex]\text{arcNPL}=2(120)=240[/tex]therefore:
[tex]\angle NML=\frac{1}{2}arcNPL=\frac{1}{2}(240)=120[/tex]answer: (3) 120°
