The equation of a circle with Center (a, b) and Radius 'r' is given by,
[tex](x-a)^2+(y-b)^2=r^2[/tex]
Given,
Center (-7, -4)
Diameter = 8
We know the radius is half of diameter.
So,
Radius = 8/2 = 4
Now we can write the equation of the cirle,
[tex]\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ (x-(-7))^2+(y-(-4))^2=4^2 \\ (x+7)^2+(y+4)^2=16 \end{gathered}[/tex]
Answer[tex](x+7)^2+(y+4)^2=16[/tex]
