Since the number on the faces of the cube are
1, 2, 3, 4, 5, 6
Then the total outcomes = 6 numbers
We need the multiples of 3
There are only 3 and 6 are the multiplies of 3, then
The outcomes = 2 numbers
The rule of probability is
[tex]P(x)=\frac{n(x)}{Tn}[/tex]
n (x) = 2
Tn = 6
[tex]P(\times3)=\frac{2}{6}[/tex]
Simplify it by dividing up and down by 2
[tex]\begin{gathered} P(\times3)=\frac{\frac{2}{2}}{\frac{6}{2}} \\ P(\times3)=\frac{1}{3} \end{gathered}[/tex]
The probability of choosing a multiple of 3 is 1/3
The answer is B
