A jet plane lands with a speed of 102 m/s and can accelerate at a maximum rate of −5.80 m/s2 as it comes to rest.(a) From the instant the plane touches the runway, what is the minimum time needed before it can come to rest? s

This is an uniformly accelerated motion, then we can use the equation:
[tex]a=\frac{v_f-v_0}{t}[/tex]In this case the final velocity is 0, the initial velocity is 102 m/s and the acceleration is -5.8 m/s²; plugging these values and solving for t we have:
[tex]\begin{gathered} -5.8=\frac{0-102}{t} \\ t=\frac{-102}{-5.8} \\ t=17.59 \end{gathered}[/tex]Therefore, the time it takes to stop is 17.59 s