the odds must be for outcomes less than or equal to 11
the possible combinations of rolling two dice are 36
the chances of getting more than 11 are only two 6 with one die 6 with another and vice versa
then we only have to remove two possibilities
[tex]36-2=34[/tex]there are 34 chances of getting no more than 11
and the probability is
[tex]\begin{gathered} \frac{34}{36} \\ =0.94 \end{gathered}[/tex]and the percentage is
[tex]0.94\times100=94[/tex]