Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 112 miles in the same time that Dana travels 106 miles. If Chuck's rate of travel is 3 miles per hour more than Dana's, and they travel the same length of time, at what speed does Chuck travel? A.56 B.64 C.53 D.48

Respuesta :

Answer:

(A)56

Explanation:

The distance covered by Chuck = 112 miles

The distance covered by Dana = 106 miles

Let Dana's rate of travel = x miles per hour

Chuck's rate of travel is 3 miles per hour more than​ Dana's, therefore:

Chuck's rate of travel = (x+3) miles per hour

Rate = Distance/Time

For Chuck

[tex]\begin{gathered} x+3=\frac{112}{t} \\ t(x+3)=112 \\ t=\frac{112}{x+3} \end{gathered}[/tex]

For Dana

[tex]\begin{gathered} x=\frac{106}{t} \\ xt=106 \\ t=\frac{106}{x} \end{gathered}[/tex]

Since they travel the same length of​ time

[tex]\begin{gathered} \frac{112}{x+3}=\frac{106}{x} \\ \text{Cross multiply} \\ 112x=106(x+3) \\ 112x=106x+318 \\ 112x-106x=318 \\ 6x=318 \\ x=\frac{318}{6} \\ x=53 \end{gathered}[/tex]

Since Chuck's speed = (x+3) miles per hour

Chuck's speed = 53+3

=56 miles per hour.