SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the formula for calculating the area of a right triangle
[tex]\begin{gathered} Area=\frac{1}{2}ab\sin\theta \\ For\text{ a right angle,} \\ \theta=90 \\ \sin90=1 \\ \therefore Area\text{ of right triangle}=\frac{1}{2}ab \end{gathered}[/tex]
STEP 2: Find the area of the bigger triangle
[tex]\frac{1}{2}\cdot7\cdot3=\frac{21}{2}=10.5cm^2[/tex]
STEP 3: Find the area of the smaller triangle
[tex]\begin{gathered} a=6cm,b=2cm \\ Area=\frac{1}{2}\cdot6\cdot2=\frac{12}{2}=6cm^2 \end{gathered}[/tex]
STEP 3: Find the difference in the areas
[tex]\begin{gathered} Area\text{ of big right triangle - Area of small triangle} \\ =10.5cm^2-6cm^2=4.5cm^2 \end{gathered}[/tex]
Hence, the difference is 4.5cm²
