Find a formula for a quadratic function with vertex at (-2,8) and y intercept (0,7)

Givens.
• The vertex is (-2,8).
,• The y-intecept is (0,7).
Given that we know the vertex and the y-intercept, we can use the standard form to find the equation.
[tex]f(x)=a(x-h)^2+k[/tex]Where h = -2, k = 8, x = 0, and f(x) = 7. Find a.
[tex]\begin{gathered} 7=a(0-(-2))^2+8 \\ 7=a(4)+8 \\ 7-8=4a \\ a=\frac{-1}{4} \end{gathered}[/tex]Once we have a, we can write the complete formula for the function.
[tex]f(x)-\frac{1}{4}(x+2)^2+8[/tex]