The area of the triangle below is 4.06 square meters. What is the length of the base?2.8 mET

ANSWER
b = 2.9 m
EXPLANATION
The area of a triangle is,
[tex]A=\frac{b\cdot h}{2}[/tex]Where b is the length of the base and h is the height of the triangle.
In this problem, we know that the area is A = 4.06 m² and the height is h = 2.8 m,
[tex]4.06m^2=\frac{b\cdot2.8m}{2}[/tex]We have to solve this equation for b. Multiply both sides by 2,
[tex]\begin{gathered} 2\cdot4.06m^2=\frac{b\cdot2.8m}{2}\cdot2 \\ \\ 8.12m^2=b\cdot2.8m \end{gathered}[/tex]And divide both sides by 2.8 m,
[tex]\begin{gathered} \frac{8.12m^2}{2.8m}=\frac{b\cdot2.8m}{2.8m} \\ \\ 2.9m=b \end{gathered}[/tex]Hence, the length of the base is 2.9 m.