distance = 13
Explanation:The given points: (0, -5) and (12, 0)
Using the distance formula:
[tex]dis\tan ce\text{ = }\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}[/tex][tex]\begin{gathered} x_1=0,y_1=-5,x_2=12,y_2\text{ = 0} \\ \text{distance = }\sqrt[]{(0-(-5))^2+(12-0)^2} \\ \text{distance = }\sqrt[]{(0+5)^2+(12)^2} \\ \text{distance = }\sqrt[]{25\text{ + 144}} \\ \end{gathered}[/tex][tex]\begin{gathered} \text{distance = }\sqrt[]{169} \\ \text{distane = 13} \end{gathered}[/tex]