Respuesta :

hello

f(3) = 5

f(4) = 10

f(5) = 15

f(6) = 20

assuming it's an arithmetic progression

common difference = f(4) - f(3) = 10 - 5 = 5

[tex]\begin{gathered} \text{common difference = 10 - 5 = 5} \\ f(n)=f(n-1)\cdot5 \end{gathered}[/tex]

the recursive formula for this sequence is f(n) = f(n - 1) * 5