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A car of weight W=16000N rests on a surface that is part of a hydraulic lift system. The piston below the car has an area of 4E-1m^2. An input force F is applied to another piston of the hydraulic system; this piston's area is 4E-4m^2. What input force F is necessary to lift the car?

A car of weight W16000N rests on a surface that is part of a hydraulic lift system The piston below the car has an area of 4E1m2 An input force F is applied to class=

Respuesta :

In order to calculate the force required, we can use the formula below:

[tex]\frac{A_1}{A_2}=\frac{F_1}{F_2}[/tex]

Using F1 = 16000, A1 = 4*10^-1, F2 = F and A2 = 4*10^-4, we have:

[tex]\begin{gathered} \frac{4\cdot10^{-1}}{4\cdot10^{-4}}=\frac{16000}{F}\\ \\ 10^3=\frac{16000}{F}\\ \\ F=\frac{16000}{10^3}\\ \\ F=16\text{ N} \end{gathered}[/tex]

Therefore the correct option is h.

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