Given that:
[tex]G=\frac{d}{1-u}[/tex]
- we cross multiply as follows:
[tex]G\times(1-u)=d[/tex]
- we divide both sides by G, as follows:
[tex]\begin{gathered} \frac{G\times(1-u)}{G}=\frac{d}{G} \\ \end{gathered}[/tex][tex]1-u=\frac{d}{G}[/tex]
- Subtract 1 from both sides of the equation:
[tex]1-u-1=\frac{d}{G}-1[/tex][tex]-u=\frac{d}{G}-1[/tex]
- multiply both sides of the equation by -1, as follows:
[tex]-u\times-1=(\frac{d}{G}-1)\times-1[/tex][tex]u=-\frac{d}{G}+1[/tex]
Therefore, we have that:
[tex]u=1-\frac{d}{G}[/tex]
or:
[tex]u=\frac{G-d}{G}[/tex]
