In the given figure, lines l, m, and n are parallel.
These parallel lines are cut by two transversal lines proportionally.
So, we can set up the following proportion.
[tex]\frac{x}{6}=\frac{11}{33}[/tex]
Let us solve for x.
[tex]\begin{gathered} \frac{x}{6}=\frac{11}{33} \\ x=6\cdot\frac{11}{33} \\ x=2 \end{gathered}[/tex]
Therefore, the value of x is 2
