Given:
AB = 21 cm
BC = 25 cm
∠A = θ
Let's find the measure of angle A.
To find the measure of angle A, apply the trigonometric ratio for tan.
We have:
[tex]\tan \theta=\frac{opposite}{\text{adjacent}}[/tex]
Where:
Opposite side is the side opposite the given angle(θ) = BC = 25 cm
Adjacent side is the side adjacent to the given angle (θ) = AB = 21 cm
Thus, we have:
[tex]\text{tan}\theta=\frac{25}{21}[/tex]
Solving further:
Take the inverse tangent of both sides
[tex]\begin{gathered} \theta=\tan ^{-1}(\frac{25}{21}) \\ \\ \theta=\tan ^{-1}(1.19) \\ \\ \theta=49.9\degree\approx50\degree \end{gathered}[/tex]
Therefore, the measure of ∠A to the nearest degree is 50°
ANSWER:
50°
