Miriam needs 8 consecutive throws to win
Here, we want to calculate the number of throws consecutively that Miriam must make into the cup to beat Ishak
Since Ishak made 48% already, Miriam must make 52%
Out of 30, she made 12;
This represents a percentage of;
[tex]\frac{12}{30}\text{ }\times\text{ 100\% = 40\%}[/tex]
Let the number of throws needed be x;
So;
[tex]\begin{gathered} \frac{x+12}{30+x}\text{ }\times\text{ 100 = 52} \\ \\ 100(x+12)\text{ = 52(30+x)} \\ \\ 100x\text{ + 1200 = 1560+52x} \\ \\ 100x-52x\text{ = 1560-1200} \\ \\ 48x\text{ = 360} \\ \\ x\text{ = }\frac{360}{48} \\ \\ x\text{ = 7.5 which is approx 8} \end{gathered}[/tex]
So what this mean is that, out of 38 throws, 20 would enter, with the last 8 being consecutive
