Explanation
In answering the question, we will make use of the fact that
For option 1
[tex]\begin{gathered} F(x)=\frac{2x-1}{3x^2} \\ The\text{ horizontal asymptote is} \\ y=0 \end{gathered}[/tex]
For option 2
[tex]\begin{gathered} f(x)=\frac{x-1}{3x} \\ \\ The\text{ horizontal assymptote is} \\ y=\frac{1}{3} \end{gathered}[/tex]
For option 3
[tex]\begin{gathered} f(x)=\frac{2x^2}{3x-1} \\ \\ There\text{ is no horizontal asymptote} \end{gathered}[/tex]
For option 4
[tex][/tex]
