Solutions
[tex]ComparingI can infer that:[tex]\begin{gathered} 5x-35<90 \\ adding\text{ }35\text{ }to\text{ }both\text{ }sides; \\ 5x<90+35 \\ 5x<125 \end{gathered}[/tex]
Divide through with the coefficient of x;
[tex]\begin{gathered} x=\frac{125}{5} \\ x=25^o \end{gathered}[/tex]
Similarly;
I can Infer that;
[tex]\begin{gathered} 5x-35>0 \\ 5x>0+35 \\ 5x>35 \\ x>\frac{35}{5} \\ x>7 \end{gathered}[/tex]
