Given:
KN is a diameter of the circle.
LP⊥KN.
MO⊥KN.
Since KN is a diameter of the circle, LP⊥KN and MO⊥KN, the diameter KN bisects the lines MO and LP.
So, NR is a perpendicular bisector to chord MO.
So, arcs MN and NO will be equal.
Similarly, since KT is a perpendicular bisector to chord LP, arcs LK and KP are equal.
Since arc LK=arc KP and arc NM=arc NO, arc KM=arc OK.
Hence, arc LM=arc OP.
Therefore, congruent arcs are
i) arc OK and arc KM.
ii) arc LM and arc OP.
