Subtracting 7/10 from the given equation we get:
[tex]\begin{gathered} \frac{3}{5}x+\frac{7}{10}-\frac{7}{10}=\frac{19}{10}-\frac{7}{10}, \\ \frac{3}{5}x=\frac{12}{10}. \end{gathered}[/tex]Now, multiplying the above equation by 5/3 we get:
[tex]\begin{gathered} \frac{3}{5}x\times\frac{5}{3}=\frac{12}{10}\times\frac{5}{3}, \\ x=\frac{4}{2}, \\ x=2. \end{gathered}[/tex]Answer:
[tex]x=2.[/tex]