let given problem as:
[tex]y=\sqrt[3]{64}[/tex]By using prime factorisation:
[tex]y=\sqrt[3]{2\times2\times2\times2\times2\times2}[/tex]By simplyfing it we can write it is:
[tex]y=\sqrt[3]{4\times4\times4}[/tex]or:
[tex]\begin{gathered} y=(4^3)^{\frac{1}{3}} \\ y=4 \end{gathered}[/tex]so the answe of cube rootof 64 is 4.
