At first, let the FCI of soccer is s and the FCI of the arena is a
Since the total FCI of them is $109.59
Then add s and a, equate the sum by 109.59
[tex]s+a=109.59\rightarrow(1)[/tex]
Since the FCI of the arena is more than the FCI of soccer by $9.41, then
Equate a by s plus 9.41
[tex]a=s+9.41\rightarrow(2)[/tex]
Substitute a in equation (1) by equation (2)
[tex]\begin{gathered} s+s+9.41=109.59 \\ 2s+9.41=109.59 \end{gathered}[/tex]
Subtract 9.41 from both sides
[tex]\begin{gathered} 2s+9.41-9.41=109.59-9.41 \\ 2s=100.18 \end{gathered}[/tex]
Divide both sides by 2
[tex]\begin{gathered} \frac{2s}{2}=\frac{100.18}{2} \\ s=50.09 \end{gathered}[/tex]
Substitute the value of s in equation (2) to find a
[tex]\begin{gathered} a=50.09+9.41 \\ a=59.5 \end{gathered}[/tex]
The answers are
FCI of soccer is $50.09
FCI of arena is $59.5
