Step 1:
Let the invested on B = m
Amount invested on A = m - 2000
Step 2
Profit is in percentage of the cost of investment
A profit is 8%
[tex]\begin{gathered} A\text{ profit = 8\% of m - 200}0 \\ =\text{ }\frac{8}{100}\text{ }\times\text{ (m - 2000)} \\ =\text{ 0.08m - 16}0 \end{gathered}[/tex][tex]\begin{gathered} B\text{ profit = 6\% of m} \\ =\text{ 0.06m} \end{gathered}[/tex]Step 3
Total profit = $1940
[tex]\begin{gathered} 0.08m\text{ - 160 + 0.06m = 1940} \\ 0.14m\text{ = 1940 + 16}0 \\ 0.14m\text{ = 2}100 \\ m\text{ = }\frac{2100}{0.14} \\ \text{m = \$15000} \end{gathered}[/tex]Final answer
She invested $15,000 in fund B
