A. O 33.836 kg m/sB. O31.903 kg m/sC. O 12.883 kg m/sD. O 19.2 kg m/sE. O 23.979 kg m/s6. An object of mass 9.5 kg was acted by a force of 14.2 N for3.6 seconds. If its initial speed was 4.0 m/s,calculate its final speed. (1 point)A) 14.189B) 16.584C) 2.015D)3.015E) 9.381

Respuesta :

Given:

The mass of the object is m = 9.5 kg

The force acting on it is F = 14.2 N

The time duration is t = 3.6 s

The initial speed is

[tex]v_i=\text{ 4 m/s}[/tex]

To calculate the final speed.

Explanation:

An impulse of an object is calculated as

[tex]Impulse\text{ = F}\times t[/tex]

It can also be written as

[tex]\begin{gathered} Impulse\text{ = change in momentum} \\ =mv_f-mv_i \end{gathered}[/tex]

So, the final velocity can be calculated by equating both the formula

[tex]\begin{gathered} F\times t=mv_f-mv_i \\ mv_f=F\times t+mv_i \\ v_f=\frac{(F\times t)+mv_i}{m} \end{gathered}[/tex]

On substituting the values, the final speed will be

[tex]\begin{gathered} v_f=\frac{(14.2\times3.6)+(9.5\times4)}{9.5} \\ =9.381\text{ m/s} \end{gathered}[/tex]

Thus, the correct choice is E