AvabellaX730553 AvabellaX730553

31-10-2022
Mathematics

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RuthiE711660 RuthiE711660

31-10-2022

We have to solve for x.

We will apply the logarithm properties.

[tex]\begin{gathered} 2^{x-1}=31 \\ \log _2(2^{x-1})=\log _2(31) \\ x-1=\log _2(31) \\ x=\log _2(31)+1 \\ x\approx4.9542+1 \\ x\approx5.9542 \end{gathered}[/tex]

Answer: x = 5.9542

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