Given that the current is I = 0.80 A
and the time taken is
[tex]\begin{gathered} t\text{ = 19 minutes} \\ =19\times60\text{ seconds} \\ =1140\text{ s} \end{gathered}[/tex]We have to find the charge, q.
The formula to calculate the charge is
[tex]q=I\times t[/tex]Substituting the values, the charge will be
[tex]\begin{gathered} q\text{ = }0.80\times1140 \\ =912\text{ C} \end{gathered}[/tex]Thus, the charge is 912 C.
