hello
to solve this qiestion, we can either use pythagorean theorem or trigonometric ratio since it's a right angled triangle
but to save time, we can use pythagorean theorem
[tex]\begin{gathered} 12^2=x^2+(6\sqrt[]{3})^2 \\ 144=x^2+108 \\ \end{gathered}[/tex]
collect like terms
[tex]\begin{gathered} x^2=144-108 \\ x^2=36 \end{gathered}[/tex]
take the square root of both sides
[tex]\begin{gathered} x^2=36 \\ x=\sqrt[]{36} \\ x=6 \end{gathered}[/tex]
from the calculations above, the value of x is equal to 6
