Answer:[tex]0.05x^7y^{-1}[/tex]Explanations:
The given expression is:
[tex](\frac{5x^3y}{12y^5x}\div\frac{x^2y}{x^4y^3})\div\frac{75x^{-2}y^{-2}}{9xy^{-1}}[/tex]
This can be simplified as
[tex]\begin{gathered} \frac{5x^3\times x^{-1}\times y\times y^{-5}}{12}\times\frac{x^4y^3}{x^2y}\times\frac{9xy^{-1}}{75x^{-2}y^{-2}} \\ \frac{5x^2y^{-4}}{12}\times x^2y^2\times\frac{9x^3y}{75} \\ \frac{45x^7y^{-1}}{900} \\ 0.05x^7y^{-1} \end{gathered}[/tex]
where A = 0.05, m = 7, n = -1
