Given:
[tex]0=4x²+3x+8.[/tex]
To find:
The solutions.
Explanation:
Here,
[tex]\begin{gathered} a=4 \\ b=3 \\ c=8 \end{gathered}[/tex]
Using quadratic formula,
[tex]\begin{gathered} x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ =\frac{-3\pm\sqrt{(-3)^2-4(4)(8)}}{2(4)} \\ =\frac{-3\pm\sqrt{9-128}}{8} \\ =\frac{-3\pm\sqrt{-119}}{8} \\ =\frac{-3\pm i\sqrt{119}}{8} \end{gathered}[/tex]
Thus, the solution is,
[tex]\frac{-3-i\sqrt{119}}{8}[/tex]
Final answer:
The correct option is D.
[tex]\frac{-3-i\sqrt{119}}{8}[/tex]
