Respuesta :
Given:
The speed of the wave is,
[tex]v=3\text{ m/s}[/tex]The distance between adjacent crests is,
[tex]1.75\text{ m}[/tex]To find:
a) What is the frequency of the waves?
b) What is the period of the waves?
Explanation:
a) The horizontal distance between two adjacent crests or troughs is known as the wavelength.
The wavelength is,
[tex]\lambda=1.75\text{ m}[/tex]The frequency is,
[tex]\begin{gathered} f=\frac{v}{\lambda} \\ =\frac{3}{1.75} \\ =1.71\text{ Hz} \end{gathered}[/tex]Hence, the frequency is 1.71 Hz.
b)
The period of waves is,
[tex]\begin{gathered} T=\frac{1}{f} \\ =\frac{1}{1.71} \\ =0.58\text{ s} \end{gathered}[/tex]Hence, the period of waves is 0.58 s.
