16. A gas occupies a volume of 777 mL at a temperature of 318 K and a pressure of 299 mm Hg. If the volume remains constant and the temperature is doubled, what will its pressure be?

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AmonteM388004 AmonteM388004 · Answer 1 · 2022-10-31T07:35:42+01:00

Answer

598 mmHg

Explanation

Given

Volume of the gas = 777 mL

Initial temperature, T₁ = 318 K

Initial pressure, P₁ = 299 mmHg

Since the temperature is double, then the final temperature = 2 x 318 K = 636 K

What to find:

The final pressure of the gas when its temperature is doubled.

Step-by-step solution:

Since the volume remains constant, then the final pressure of the gas can be calculated using Amonton's law formula below:

[tex]\begin{gathered} \frac{P_1}{T_1}=\frac{P_2}{T_2} \\ \\ \Rightarrow P_2=\frac{P_1T_2}{T_1} \end{gathered}[/tex]

Putting the values of the parameters into the formula, we have

[tex]P_2=\frac{299mmHg\times636K}{318K}=598\text{ }mmHg[/tex]

The final pressure of the gas when its temperature is doubled is 598 mmHg