Given
[tex]\begin{gathered} \cos\theta=-\frac{5}{13} \\ \sin\theta<0 \end{gathered}[/tex]
To identify the quadrant of θ and the value of sinθ.
Explanation:
It is given that,
[tex]\begin{gathered} \cos\theta=-\frac{5}{13} \\ \sin\theta<0 \end{gathered}[/tex]
Since
[tex]\begin{gathered} \cos\theta=-\frac{5}{13}<0 \\ \sin\theta<0 \end{gathered}[/tex]
Then, the quadrant of θ is III.
Also,
[tex]\sin\theta=-\frac{12}{13}[/tex]
Hence, the answer option C) Quadrant: III, sinθ =-12/13.
