Respuesta :

[tex]10x^2+79x-8[/tex]

Factor:

The coefficient of x² is 10 and the constant term is -8, so:

[tex]10\times-8=-80[/tex]

The factors of 80 which sum to 79 are -1 and 80, hence:

[tex]10x^2+79x-8=10x^2+80x-x-8[/tex]

Group like terms:

[tex]10x^2+80x-x-8=8(10x-1)+x(10x-1)[/tex]

Factor 10x-1 from the previous expression:

[tex](10x-1)(8+x)[/tex]