[tex]\begin{gathered} \text{ The area of a triangle is } \\ A=\frac{1}{2}b\cdot h, \\ \text{where b is the base lenght, and h is the height.} \\ t\text{hus the area of the triangle is } \\ \frac{1}{2}4\cdot4=\frac{16}{2}=8 \end{gathered}[/tex][tex]\begin{gathered} Thus\text{ the total area is the sum of the areas of the rectangles plus the area of the triangle} \\ A_{\text{total}}=8+(12\cdot4)+(6\cdot(4+5+5))+(5\cdot4) \\ =8+(48)+(6\cdot14)+20 \\ =8+48+84+20 \\ =160 \end{gathered}[/tex]
The total Area is then 160 square units.
