We are given that 221J of work is required to lift a mass of 4.75 meters. The amount of work is determined by the following equation:
[tex]W=Fd[/tex]
Where:
[tex]\begin{gathered} F=\text{ force} \\ d=\text{ distance} \end{gathered}[/tex]
The force is equivalent to the combined weight if the dog and the basket multiplied by the acceleration of gravity:
[tex]F=mg[/tex]
The distance is the height that the basket is lifted:
[tex]d=h[/tex]
Now, we substitute in the equation:
[tex]W=mgh[/tex]
Now, we divide by "gh":
[tex]\frac{W}{gh}=m[/tex]
Now, we substitute the values:
[tex]\frac{221J}{(9.8\frac{m}{s^2})(4.75m)}=m[/tex]
Solving the operations:
[tex]4.75kg=m[/tex]
Therefore, the combined mass is 4.75 kg.
