Respuesta :

[tex]3^{-2}[/tex]

When we have negative exponents we can rewrite them as apositive exponent using a fraction

[tex]a^{-b}=\frac{1}{a^b}[/tex]

according to this the problem cam be writen as

[tex]3^{-2}=\frac{1}{3^2}=\frac{1}{9}[/tex]

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