To find the molar mass of Prevacid, we just have to add the molar mass of each element multiplied by their subscript.
[tex]16\cdot12.01+14\cdot1.01+3\cdot18.998+3\cdot14+2\cdot15.999+1\cdot32.07=_{}369.6\cdot\frac{g}{\text{mol}}[/tex](a) The molar mass of Prevacid is 369.6 g/mol.
Now, let's find the representation of fluorine in the compound.
[tex]\frac{3\cdot18.998}{369.6}=0.1542[/tex]Fluorine represents 15.42% of the compound. So, if we have 0.75 moles of Prevacid, we would have 0.1542x0.75 = 0.12 moles of Fluorine.
(b) There are 0.12 moles of fluorine in 0.75 moles of Prevacid.
Then, we know that in 1 mole of Prevacid, there are 16 carbon atoms. So,
[tex]0.75\text{mol}\cdot\frac{16\text{ carbon atoms}}{1\text{mol}}=12\text{ carbon atoms}[/tex](c) There are 12 carbon atoms in 0.75 moles of Prevacid.
