First, find the slope of the line using the given two points (-2,5) and (3,0)
[tex]\begin{gathered} \text{Let} \\ (x_1,y_1)=(-2,5) \\ (x_2,y_2)=(3,0) \\ \\ m = \dfrac{y_2 - y_1}{x_2 - x_1} \\ m=\dfrac{0-5}{3-(-2)} \\ m=\dfrac{-5}{3+2} \\ m=\frac{-5}{5} \\ m=-1 \end{gathered}[/tex]Now that we have the slope, solve for the equation using the point-slope form, in this instance we will use (-2,5)
[tex]\begin{gathered} y-y_1=m\left(x-x_1\right) \\ y-5=-1\lparen x-(-2)) \\ y-5=-x-2 \\ x=-y-2+5 \\ x=-y+3 \end{gathered}[/tex]The equation therefore (in terms of x) is x = -y + 3.
