Answer:
The function h(x-2) is;
[tex]h(x-2)=2x^2-11x+14[/tex]Explanation:
We want to find the value of h(x-2) if the function h(x) is;
[tex]h(x)=2x^2-3x[/tex]We can derive the function h(x-2) by substituting/replacing x with x-2;
[tex]\begin{gathered} h(x)=2x^2-3x \\ h(x-2)=2(x-2)^2-3(x-2) \\ h(x-2)=2(x-2)(x-2)-3(x-2) \\ h(x-2)=2(x^2-2x-2x+4)-3(x-2) \\ h(x-2)=2(x^2-4x+4)-3(x-2) \\ h(x-2)=2x^2-8x+8-3x+6 \\ h(x-2)=2x^2-8x-3x+6+8 \\ h(x-2)=2x^2-11x+14 \end{gathered}[/tex]The function h(x-2) is;
[tex]h(x-2)=2x^2-11x+14[/tex]