Answer
0.15 M solution of LiOH.
Explanation
What is given:
Molarity of HCl = 0.22 M
Volume of HCl used = 12.3 mL
Volume of LiOH used = 18.0 mL
What to find:
To calculate the molarity of LiOH.
Step-by-step solution:
Step 1: Write the balanced chemical equation for the reaction.
HCl + LiOH → LiCl + H₂O
Step 2: Calculate the molarity of LiOH solution.
Using:
[tex]\begin{gathered} \frac{C_aV_a}{n_a}=\frac{C_bV_b}{n_b} \\ \\ C_a=0.22\text{ }M,V_a=12.3\text{ }mL,n_a=1 \\ \\ C_b=unknown,V_b=18.0\text{ }mL,n_a=1 \\ \\ \Rightarrow\frac{0.22\text{ }M\times12.3\text{ }mL}{1}=\frac{C_b\times18.0\text{ }mL}{1} \\ \\ C_b=\frac{0.22\text{ }M\times12.3\text{ }mL\times1}{18.0\text{ }mL\times1}=\frac{27.06}{18.0}=0.15\text{ }M \end{gathered}[/tex]Hence, the molarity of LiOH solution is 0.15 M
