For this case we have the following expression given:
[tex]\frac{-6}{6(-2-h)}+3+j\text{ , h= }3\text{, j=6}[/tex]We can begin doing this:
[tex]\frac{-6}{-6(2+h)}+3+j[/tex]We can cancel -6 and we got:
[tex]\frac{1}{2+h}+3+j[/tex]Now we can replace h=3 and j= 6 and we got:
[tex]\frac{1}{2+3}+3+6=\text{ }\frac{1}{5}+9=\text{ }\frac{46}{5}[/tex]